0=-16x^2+43x+22

Solution for 0=-16x^2+43x+22 equation:

0=-16x^2+43x+22

We move all terms to the left:

0-(-16x^2+43x+22)=0

We add all the numbers together, and all the variables

-(-16x^2+43x+22)=0

We get rid of parentheses

16x^2-43x-22=0

a = 16; b = -43; c = -22;
Δ = b2-4ac
Δ = -432-4·16·(-22)
Δ = 3257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{3257}}{2*16}=\frac{43-\sqrt{3257}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{3257}}{2*16}=\frac{43+\sqrt{3257}}{32}
$